单片机键盘的应用 -

作业1：数码管前三位数显示一个跑表，从000到999,之间以百分之一秒的速度运行，当按下key1时跑表停止，再次按下时跑表开始

本文引用地址: http://www.21ic.com/app/mcu/201807/783054.htm

#include

#define uint unsigned int

#define uchar unsigned char

sbit dula =P2^6;

sbit wela = P2^7;

sbit key1 = P3^7;

uchar aa,flag,bai,shi,ge,tt;

uint num,bb;

void init();

void keyscan();

void delay(uint z);

void display(uchar bai,uchar shi,uchar ge);

uchar code table[]={0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71};

main()

{

init();

P3 = 0xff;

while(1)

{

display(bai,shi,ge);

if(key1==0)//检测是否按下

{

delay(10);

if(key1==0)//确实按下了

{

TR0 = 0;//定时器停止

bb ++;//计算按下的次数

while(!key1)

display(bai,shi,ge);

if(bb %2==0)

{

TH0 =(65536-50000)/256;//装初值

TL0 =(65536-50000)%256;

TR0 = 1;//重启定时器

}

}

}

}

}

void delay(uint z)

{

uint x,y;

for(x=z;x>0;x--)

for(y=110;y>0;y--);

}

void init()

{

TMOD = 0x01;

TH0 =(65536-50000)/256;

TL0 =(65536-50000)%256;

EA = 1;

ET0 = 1;

TR0 = 1;

}

void time0()interrupt 1

{

TH0 =(65536-50000)/256;

TL0 =(65536-50000)%256;

aa++;

if(aa==2)

{

aa = 0;

num ++;

if(num==1000)

num=0;

}

bai = num/100;

shi = num/10%10;

ge = num%10;

}

void display(uchar bai,uchar shi,uchar ge)

{

wela = 1;

P0 = 0xfe;

wela = 0;

P0 = 0x0;//消影操作

dula = 1;

P0 = table[bai];

dula = 0;

tt = 25;

while(tt--);

dula = 1;//关灯操作，高速度扫描时必备

P0 = 0;

dula = 0;

wela = 1 ;

P0 = 0xfd;

wela = 0;

P0= 0x0;//消影操作

dula = 1;

P0 = table[shi];

dula = 0;

tt = 25;

while(tt--);

dula = 1;//关灯操作，高速度扫描时必备

P0 = 0;

dula = 0;

wela = 1;

P0 = 0xfb;

wela = 0;

P0 = 0x0;//消影操作

dula = 1;

P0 = table[ge];

dula =0;

tt=25;

while(tt --);

dula = 1;//关灯操作，高速度扫描时必备

P0 = 0;

dula = 0;

}

在上题目的基础上，用另外三个独立键盘实现按下第一个时计数停止，按下第二个时计数开始，按下第三个时计数清零重新开始

#include

#define uint unsigned int

#define uchar unsigned char

sbit dula =P2^6;

sbit wela = P2^7;

sbit key1 = P3^3;

sbit key2 = P3^4;

sbit key3 = P3^5;

sbit key4 = P3^6;

uchar aa,flag,bai,shi,ge,tt;

uint num,bb;

void init();

void keyscan();

void delay(uint z);

void display(uchar bai,uchar shi,uchar ge);

uchar code table[]={0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71};

main()

{

init();

P3 = 0xff;

while(1)

{

display(bai,shi,ge);

if(key1==0)//检测是否按下

{

delay(10);

if(key1==0)//确实按下了

{

TR0 = 0;//定时器停止

while(!key1)

display(bai,shi,ge);

TR0 = 1;//重启定时器

}

}

if(key2==0)

{

delay(10);

if(key2==0)

{

TR0 = 0;//定时器停止

while(!key2)

display(bai,shi,ge);

}

}

if(key3==0)

{

delay(10);

if(key3==0)

{

TH0=(65536-50000)/256;

TL0 = (65536-50000)%256;

TR0 = 1;//重启定时器

while(!key3)

display(bai,shi,ge);//不加入这句话有很大的bug

}

}

if(key4==0)

{

delay(10);

if(key4==0)

{

num = 0;//重新开始计数

while(!key4)

display(bai,shi,ge);

}

}

}

}

void delay(uint z)

{

uint x,y;

for(x=z;x>0;x--)

for(y=110;y>0;y--);

}

void init()

{

TMOD = 0x01;

TH0 =(65536-50000)/256;

TL0 =(65536-50000)%256;

EA = 1;

ET0 = 1;

TR0 = 1;

}

void time0()interrupt 1

{

TH0 =(65536-50000)/256;

TL0 =(65536-50000)%256;

aa++;

if(aa==2)

{

aa = 0;

num ++;

if(num==1000)

num=0;

}

bai = num/100;

shi = num/10%10;

ge = num%10;

}

void display(uchar bai,uchar shi,uchar ge)

{

wela = 1;

P0 = 0xfe;

wela = 0;

P0 = 0x0;//消影操作

dula = 1;

P0 = table[bai];

dula = 0;

tt = 25;

while(tt--);

dula = 1;//关灯操作，高速度扫描时必备

P0 = 0;

dula = 0;

wela = 1 ;

P0 = 0xfd;

wela = 0;

P0= 0x0;//消影操作

dula = 1;

P0 = table[shi];

dula = 0;

tt = 25;

while(tt--);

dula = 1;//关灯操作，高速度扫描时必备

P0 = 0;

dula = 0;

wela = 1;

P0 = 0xfb;

wela = 0;

P0 = 0x0;//消影操作

dula = 1;

P0 = table[ge];

dula =0;

tt=25;

while(tt --);

dula = 1;//关灯操作，高速度扫描时必备

P0 = 0;

dula = 0;

}

作业3：按下16个矩阵键盘依次在数码管上显示1到16的平方

#in